If O2 gas is bubbled through water at 303K the number of millimoles
If O2 gas is bubbled through water at 303K the number of millimoles
The number of millimoles of O2 gas that dissolve in 1 liter of water at 303 K is approximately 43 millimoles, calculated using Henry's Law and
If $$ gas is bubbled through water at $293K$ , how many millimoles of $$ gas would dissolve in $1Litre$ water Assuming that $$ exerts a
if i won the lottery i wouldn''t tell anyone The correct answer is p=KH× bar=×103 bar×mol of O2mol of =×103 ×mol of O21000=×nO2×18⇒nO2=×10−3⇒mmol of O2=1
if o2 gas is bubbled through water at 303k o2 is bubbled through water at 293 k assuming that o2 exerts a partial pressure If N2 gas is bubbled through water at 293 K, how many
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